删除一个StringBuilder的最后一个字符
When you have to loop through a collection and make a string of each data separated by a delimiter, you always end up with an extra delimiter at the end, e.g.
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for (String serverId : serverIds) {
sb.append(serverId);
sb.append(",");
}
Gives something like : serverId_1, serverId_2, serverId_3,
I would like to delete the last character in the StringBuilder (without converting it because I still need it after this loop).
Others have pointed out the deleteCharAt method, but here’s another alternative approach:
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String prefix = "";
for (String serverId : serverIds) {
sb.append(prefix);
prefix = ",";
sb.append(serverId);
}
Alternatively, use the Joiner class from Guava :)
As of Java 8, StringJoiner is part of the standard JRE.
Another simple solution is:
```plain text sb.setLength(sb.length() - 1);
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A more complicated solution:
The above solution assumes that sb.length() > 0 … i.e. there is a “last character” to remove. If you can’t make that assumption, and/or you can’t deal with the exception that would ensue if the assumption is incorrect, then check the StringBuilder’s length first; e.g.
```java
// Readable version
if (sb.length() > 0) {
sb.setLength(sb.length() - 1);
}
or
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// Concise but harder-to-read version of the above
sb.setLength(Math.max(sb.length() - 1, 0));
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sb.deleteCharAt(sb.length()-1)
In this case,
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sb.setLength(sb.length() - 1);
is preferable as it just assign the last value to ‘\0’ whereas deleting last character does System.arraycopy
As of Java 8, there’s a new StringJoiner class built in.
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StringJoiner sj = new StringJoiner(", ");
for (String serverId : serverIds) {
sj.add(serverId);
}
2016年09月25日25分09秒
Another alternative
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for (String serverId : serverIds) {
sb.append(",");
sb.append(serverId);
}
sb.deleteCharAt(0);
Alternatively,
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StringBuilder result = new StringBuilder();
for (String string : collection) {
result.append(string);
result.append(",");
}
return result.substring(0, result.length() - 1);
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StringBuilder sb = new StringBuilder();
sb.append("abcdef");
sb.deleteCharAt(sb.length() - 1);
assertEquals("abcde", sb.toString()); // true
Just get the position of the last character occurrence.
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for (String serverId : serverIds) {
sb.append(serverId);
sb.append(",");
}
sb.deleteCharAt(sb.lastIndexOf(","));
Since lastIndexOf will perform a reverse search, and you know that it will find at the first try, performance won’t be an issue here.
Yet another alternative:
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public String join(Collection<String> collection, String seperator) {
if (collection.isEmpty()) return "";
Iterator<String> iter = collection.iterator();
StringBuilder sb = new StringBuilder(iter.next());
while (iter.hasNext()) {
sb.append(seperator);
sb.append(iter.next());
}
return sb.toString();
}
I am doing something like this:
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StringBuilder stringBuilder = new StringBuilder();
for (int i = 0;
i < value.length;
i++) {
stringBuilder.append(values[i]);
if (i < value.length - 1) {
stringBuilder.append(", ");
}
}
With Java-8 you can use static method of String class,
String#join(CharSequence delimiter,Iterable
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public class Test {
public static void main(String[] args) {
List<String> names = new ArrayList<>();
names.add("James");
names.add("Harry");
names.add("Roy");
System.out.println(String.join(",", names));
}
}
OUTPUT
```plain text James,Harry,Roy
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To avoid reinit(affect performance) of prefix use TextUtils.isEmpty:
```java
String prefix = "";
for (String item : list) {
sb.append(prefix);
if (TextUtils.isEmpty(prefix))
prefix = ",";
sb.append(item);
}
Yet another solution similar to the “prefix” solution above avoids multiple prefix assignments in the loop. i.e. Just in case the optimizer does not unroll the first loop iteration.
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StringBuilder sb = new StringBuilder();
boolean firstEntry = true;
for (String serverId : serverIds) {
if (firstEntry)
firstEntry = false;
else
sb.append(",");
sb.append(serverId);
}
You can use:
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string finalString=sb.Remove(sb.Length - 1, 1).ToString();